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I would like to know if L = 0.
l.png 2.18K
4 downloadsSo far I got up to here:
2.png 1.35K
3 downloadsI have no clue what I should do from here.
Thank you in advance.
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#1
Posted Nov 26, 2011 - 21:08
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My teacher haven't taught the class how to use the ratio test. I want to apply the ratio test for my math portfolio and unfortunately it's due on Monday, therefore I cannot ask my teacher how to use the ratio test.
I would like to know if L = 0.
l.png 2.18K
4 downloads
So far I got up to here:
2.png 1.35K
3 downloads
I have no clue what I should do from here.
Thank you in advance.
I would like to know if L = 0.
l.png 2.18K
4 downloadsSo far I got up to here:
2.png 1.35K
3 downloadsI have no clue what I should do from here.
Thank you in advance.
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#2
Posted Nov 26, 2011 - 22:36
kiwi.at.heart
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At this point you would sub in for n as n-->∞
As n-->∞, n+1-->∞ so L-->0
As n-->∞, n+1-->∞ so L-->0
#3
Posted Nov 26, 2011 - 23:12
rFumachi
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Capture.GIF 6.65K
4 downloadsWhy do you want to know if L = 0? It is enough to know that L is less than 1, to know that the series converges absolutely.
What portfolio are you doing?
#4
Posted Nov 26, 2011 - 23:19
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rFumachi, on Nov 26, 2011 - 23:12, said:
Capture.GIFWhy do you want to know if L = 0? It is enough to know that L is less than 1, to know that the series converges absolutely.
What portfolio are you doing?
I'm working on infinite summation
[Edit]
Another question... How is |1/(n+1)| = 0?
Thanks in advance
Edited by Excluded, Nov 26, 2011 - 23:30.
#5
Posted Nov 26, 2011 - 23:37
The Economist
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Excluded, on Nov 26, 2011 - 23:19, said:
rFumachi, on Nov 26, 2011 - 23:12, said:
Capture.GIFWhy do you want to know if L = 0? It is enough to know that L is less than 1, to know that the series converges absolutely.
What portfolio are you doing?
I'm working on infinite summation
[Edit]
Another question... How is |1/(n+1)| = 0?
Thanks in advance
The lim of |1/(n+1)| as n tends to infinity is zero.
#6
Posted Nov 26, 2011 - 23:51
rFumachi
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When you divide 1 by a number that is increasingly larger (like infinity + 1), then the answer will be smaller, tending to zero. If you have any doubt graph it 
Edited by rFumachi, Nov 26, 2011 - 23:55.
#7
Posted Nov 27, 2011 - 00:03
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oh right, thanks~~ i was letting n= 0 thus 1/(0)+1 = 1 Although this is true, I just needed to let n continue to infinity.
i was letting n= 0 thus 1/(0)+1 = 1 Although this is true, I just needed to let n continue to infinity.
#8
Posted Nov 27, 2011 - 00:10
rFumachi
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Excluded, on Nov 27, 2011 - 00:03, said:
oh right, thanks~~ i was letting n= 0 thus 1/(0)+1 = 1 Although this is true, I just needed to let n continue to infinity.
i was letting n= 0 thus 1/(0)+1 = 1 Although this is true, I just needed to let n continue to infinity.
Self-studying series isn't that easy 
