mGlala Posted April 4, 2008 Report Share Posted April 4, 2008 Can anyone help me with the parabola investigation? I am stuck in number 5 and 6. Thanks!Sl=x1-x2Sr=x3-x4D= abs( Sl-Sr)5.Determine whether a similar conjecture can be made for cubic polynomials6. Consider whether the conjecture might be modified to include higher order polynomials. Reply Link to post Share on other sites More sharing options...
loopstyle Posted April 7, 2008 Report Share Posted April 7, 2008 Doing the same one.. working on Q4 right now..I'll post if i get to 5&6 tonight Reply Link to post Share on other sites More sharing options...
ezex Posted April 8, 2008 Report Share Posted April 8, 2008 I'd want to help but there's not enough information...mind giving me some more info? Reply Link to post Share on other sites More sharing options...
loopstyle Posted April 8, 2008 Report Share Posted April 8, 2008 I'd want to help but there's not enough information...mind giving me some more info? The guy is asking about the last two questions... which builds up on 4-5 previous questions.. So unless you really want to spend 4 hours knowing what we're on about.. But to whoever is doing this.. QUESTION 6!? Reply Link to post Share on other sites More sharing options...
StriveR` Posted April 27, 2008 Report Share Posted April 27, 2008 doing the same question as well T_T .get stuck in number 5 too >< Reply Link to post Share on other sites More sharing options...
dea.o6 Posted April 28, 2008 Report Share Posted April 28, 2008 dont know about the cubical equation. there must be a conjecture too somewhere. Reply Link to post Share on other sites More sharing options...
Eyas Posted May 1, 2008 Report Share Posted May 1, 2008 .. anything about these points guys? I've made a conjecture for cubic polynomials but I don't see how it can be generalized for all polynomials, since its not directly related to the first conjecture to begin with Reply Link to post Share on other sites More sharing options...
jbhasin Posted May 1, 2008 Report Share Posted May 1, 2008 (edited) I had this task, finished it in March - there IS a conjecture for higher degree polynomials - when I did it, once I got the cubic conjecture, the higher level+ ones were all the same. If you aren't getting that, go back and check your quadratic conjecture and make sure you have it working with any parabola/lines, then move on to the cubics. Anyway, people in my class had a lot of difficulty getting the cubics...they weren't sure about how to get D. It took me a while, but you need to think about the relationships between the equations. Sorry, I don't know how much I'm allowed to help you since I've already done it.jbhasin Edited May 1, 2008 by jbhasin Reply Link to post Share on other sites More sharing options...
Eyas Posted May 2, 2008 Report Share Posted May 2, 2008 I'm pretty sure my quadratic conjecture is correct, I've done the proof and everything and it does work for all sorts of lines. The cubic one... the conjecture I did does work for all the lines I try, but it doesn't seem to have dependencies.. I'm not sure how much I could say as well, but the quadretic for example depended on several variables for the lines and the parabola itself, changing the values in a similar manner for cubic polynomials resulted in the same expected outcome for D.. which means I either came up with a super-conjecture here of I've missed something Reply Link to post Share on other sites More sharing options...
jbhasin Posted May 3, 2008 Report Share Posted May 3, 2008 (edited) Well look at the relationships between the graphs:parabolas and linear eqs interceptingtake a look at how you got D for the cubics...nth-degree polynomial and ...Hopefully that doesn't make it too easy.jbhasin Edited May 3, 2008 by jbhasin Reply Link to post Share on other sites More sharing options...
sushi Posted May 5, 2008 Report Share Posted May 5, 2008 (edited) Hi,I have a serious problem with tasks 5 and 6.I cannot figure out what I am supposed to find in 5. Anything that follows any patterns is that when I subtract all x's in a similar way as it was in previous exercises D is always 0. But it seems still quite illogical. Can anyone confirm if it is correct? Or maybe somebody would be eager to help me? Please help me somehow! Edited January 18, 2010 by sweetnsimple786 Please don't put your email in a post. Reply Link to post Share on other sites More sharing options...
Eyas Posted May 5, 2008 Report Share Posted May 5, 2008 When I read what jbhasin told me.. I just thought I couldn't make use of it, and I didn't.. but he seemed afraid that "it would make it too easy" and I kept thinking "no it doesn't".. but I literally thought of the solution WHILE I WAS ASLEEP (we IB victims go through stuff like that.. y'all know that) and so I understand now that saying anything more than what has been mentioned is... just... too.. direct. Reply Link to post Share on other sites More sharing options...
sushi Posted May 5, 2008 Report Share Posted May 5, 2008 Ok, thanks a lot. I'll keep trying, but today my brain is devastated by maths and tok.According to what you say it should be quite easy and even obvious, am I right? Reply Link to post Share on other sites More sharing options...
jlky1256 Posted May 13, 2008 Report Share Posted May 13, 2008 Hi. I am also doing this portfolio on parabolas.I am stuck at 5. I have come up with many unique observations like D=0 and that the sum of the roots on the y=x line and y=2x lines will give the sum of the roots (r1+r2+r3). But what's the point of all these? Must the conjecture be the same as the one from Q1 to Q4.Thanks Reply Link to post Share on other sites More sharing options...
Blueshadow Posted May 18, 2008 Report Share Posted May 18, 2008 Does anybody know if the two intersecting lines MUST be straight lines? Reply Link to post Share on other sites More sharing options...
nobita89vn Posted May 19, 2008 Report Share Posted May 19, 2008 hmm seems like everyone got the same prob... hmm my deadline is in 2 days time Reply Link to post Share on other sites More sharing options...
nobita89vn Posted May 19, 2008 Report Share Posted May 19, 2008 Does anybody know if the two intersecting lines MUST be straight linesdefinitely it must be straight lines , otherwise what? you want to change it into curve??? I think should follow y=ax+b haha I just finish question 2 ) 10 pages so far , not too bad ) another 10 for question 3 and another 10 for question 4 will sound good =)) omg Reply Link to post Share on other sites More sharing options...
deissi Posted May 19, 2008 Report Share Posted May 19, 2008 definitely it must be straight lines , otherwise what? you want to change it into curve??? I think should follow y=ax+b haha I just finish question 2 ) 10 pages so far , not too bad ) another 10 for question 3 and another 10 for question 4 will sound good =)) omghmm this is type 1 you know. you don't want to make it too long, your examiner will either commit suicide for having to read 40 pages or then mark you down for being too wordy in the communication section. Reply Link to post Share on other sites More sharing options...
Eyas Posted May 20, 2008 Report Share Posted May 20, 2008 Hmm.. whats the average length of a type 1 IA? Mine in total turned out to be ~24 pages but with spacing for graphs, etc. but I covered all points and tried not to be repetitive. so I don't know about that.. Reply Link to post Share on other sites More sharing options...
finqui Posted May 21, 2008 Report Share Posted May 21, 2008 I red in other thread that D is always equal to zero (D=0) for Q5 and Q6. I investigated it, but this answer only works for Q5. When I try with polynomials higher I get numbers like 0.00153..., very closely to zero, but no zero. Can somebody help us? Thank you in advance =)P.D. Sorry for my English, I am not a native speaker of English ^^ Reply Link to post Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.