Guest ajie1020 Posted April 28, 2008 Report Share Posted April 28, 2008 [quote name='deissi' post='14634' date='Apr 7 2008, 09:15 AM']I did logarithm bases (type I), pretty simple. I'm not familiar with the BMI project, is it modelling (type II) or algebraic (type I)?[/quote] Hey do you think you could help me with the logarithm bases? I dont quite understand what the are looking for when it says " let logaX=c and logbX=d. find the general statement that expresses logabX in terms of cd." thanks! Reply Link to post Share on other sites More sharing options...
deissi Posted April 29, 2008 Report Share Posted April 29, 2008 [quote name='ajie1020' post='15694' date='Apr 28 2008, 11:05 PM']Hey do you think you could help me with the logarithm bases? I dont quite understand what the are looking for when it says " let logaX=c and logbX=d. find the general statement that expresses logabX in terms of cd." thanks! [/quote] Well my first tip is to look at the logarithms before this logaX=c and logbX=d thing. If you were able to solve them and see the pattern, you know it for logaX=c and logbX=d as well. If you're struggling with what is meant by log[sub]ab[/sub]x in terms of c and d, what they mean is for example: say you have log[sub]a[/sub]x = log[sub]2[/sub]4 and log[sub]b[/sub]x = log[sub]8[/sub]4 The variables [i]c[/i] and [i]d[/i] are the answers of these two logarithms, and you should know how to find them. c = log[sub]2[/sub]4 and d = log[sub]8[/sub]4 For both these logarithms the value x, 8, stays the same, but the variable is a and b, the "small number". So what is meant by log[sub]ab[/sub]x is a logarithm that combines the first two logarithms, log[sub]a[/sub]x and log[sub]b[/sub]x Here ab = a * b, so using the examples we would find that ab = 2*8 = 16 If you still are in need of help, don't hesitate to ask ! Reply Link to post Share on other sites More sharing options...
youcantstopthebeat Posted May 12, 2008 Report Share Posted May 12, 2008 (edited) I understand what you're saying, deissi, but I'm still confused!! Maybe you can give me a hint on how to figure out the general statement... I'm confused, because in the sequences above the logaX=c logbX=d question, I wrote my answers in form p/q, found the pattern and figured out how to calculate the third term for each sequence (the numerator of all three answers is the same, but the demoninators are different; you add the denominators, i.e. q values, of the first two answers to find q of the third, right?) But I don't understand how you can find the value of logabX, when the numerator is different and denominator is the same (as logaX = c/1 and logbX is d/1)... or maybe I'm taking the wrong approach to the question?? ~~~ Ignore my post, I finally figured it out Edited May 13, 2008 by youcantstopthebeat Reply Link to post Share on other sites More sharing options...
hellogoodbye Posted June 1, 2008 Report Share Posted June 1, 2008 do you happen to understand how to do the first part? i'm not quite sure about the p and q thing and how to write out the answers. thanks! Reply Link to post Share on other sites More sharing options...
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