msingla Posted September 30, 2014 Report Share Posted September 30, 2014 I was wondering if anyone would be able to fully explain the following question: Ethyne (C2H2), reacts with oxygen according to the equation below. What volume of oxygen (in dm3) reacts with 0.40 cm3 of C2H2? 2C2H2 (g) + 5O2 (g) --> 4CO2 (g) + 2H2O (g) Thanks! Reply Link to post Share on other sites More sharing options...
Chirag Modhwadia Posted September 30, 2014 Report Share Posted September 30, 2014 it is a simple application of Gay-Lussac's Law. as the moles of Ethyne is 2 and volume is 0.40, 1 mole is 0.20 dm3...therefore, on taking the ratio of oxygen as 5, multiply 0.20 with 5 which is 1.0 dm3 1 Reply Link to post Share on other sites More sharing options...
Chirag Modhwadia Posted September 30, 2014 Report Share Posted September 30, 2014 sorry the answer is 1 cm3 Reply Link to post Share on other sites More sharing options...
msingla Posted September 30, 2014 Author Report Share Posted September 30, 2014 I hope that I am not doing your homework for you!!!Anyway, from the balanced equation, it can be said that 2 volumes of C2H2 react with 5 volumes of O2 to form 4 volumes of CO2 and 2 volumes of H2O.So the ratio of C2H2 to O2 is 2:5 (you could simplify this to 1 : 2.5 if it makes it easier).If you had 1 dm3 of C2H2 it would react with 2.5 dm3 of O2.As you only have 0.40cm3, it will react with 2.5 x 0.40 = 1cm3 of O2,See my video here:http://youtu.be/mXgCynmnkgwYou are not, I'm just studying for my chemistry text on Friday, but thank you for your answer! Reply Link to post Share on other sites More sharing options...
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