Hrishi98 Posted February 6, 2015 Report Share Posted February 6, 2015 Guys,How do I find the integral of (secx - tanx)^2 ????? Reply Link to post Share on other sites More sharing options...
mechnight Posted February 6, 2015 Report Share Posted February 6, 2015 First expand the square, and then do each part of the sum separately - introducing new variables and/or substitutions should do. If you need any further help, feel free to write back 1 Reply Link to post Share on other sites More sharing options...
Yuki Kuran Posted February 7, 2015 Report Share Posted February 7, 2015 (secX)^2 - 2secXtanX + (tanx)^2and then you integral them partially. i.e int of (secX)^2 is tanX + C int of -2secXtanX is -2secX +C(tanX)^2=(secX)^2 -1, thus, int of (tanX)^2 is equal to the int of (secX)^2-1 which is tanX - X +Coveral int is tanX-2secX+tanX-X+C = 2tanX-2secX-X+C 1 Reply Link to post Share on other sites More sharing options...
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