A_Happy_Monkey Posted February 12, 2015 Report Share Posted February 12, 2015 (edited) Just saying, I will be starting pre- IB in like 11/12 months (got accepted today), so please don't judge my incompetency I need to find out the surface area of: (a) a trapezoid with a height of 0.05m, and bases of 0.05m and 0.03m.(b) a rectangle with sides 0.05m and 0.02m. I have to add the areas together- however I keep getting an answer of 0.003 m2!What am I doing wrong? Edited February 12, 2015 by A_Happy_Sheep Reply Link to post Share on other sites More sharing options...
IbTrojan Posted February 13, 2015 Report Share Posted February 13, 2015 Does the question ask for an answer in specific units? Or are you to keep your answer in meters squared? Reply Link to post Share on other sites More sharing options...
CkyBlue Posted February 13, 2015 Report Share Posted February 13, 2015 That's the answer I get too; there shouldn't be anything wrong with it if you're doing what you're asking us. Maybe reread the question and see if you're not interpreting it correctly? Reply Link to post Share on other sites More sharing options...
A_Happy_Monkey Posted February 13, 2015 Author Report Share Posted February 13, 2015 Alright, thanks guys. I was kind of doubting my answer as it's like less than a square millimeter I still find the answer a bit unrealistic, but I'll just go with it. Many thanks! Reply Link to post Share on other sites More sharing options...
TDgen47@IB Posted February 16, 2015 Report Share Posted February 16, 2015 The entire working of the problem would be somewhat like this. See if you have done this way:Area for trapezoid = 1/2 * (a+b) * h Substituting we get, 1/2 * (0.03+0.05) * 0.05 which is equal to 0.0020 m^2Are of rectangle = l*bSubstituting we get, 0.02*0.05 which is equal to 0.0010 m^2Adding theses two values we get 0.003 m^2The answer you got is correct! Don't doubt this answer as there is a difference between millimeter and square millimeter , and a huge one that too. Reply Link to post Share on other sites More sharing options...
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