Jump to content

Recommended Posts

Hi!

 

I'm having trouble with an integration problem.

 

 

2π × integral between 0 and 6 of (0.02x^3-0.39x^2+1.77x+0.18) × (sqrt(0.0036x^4-0.0936x^3+0.8208x^2-2.7612x+4.1329)) dx

 

Does anyone know how to solve it or have any suggestions?

 

Thanks heaps!

Link to post
Share on other sites

Hi!

 

I'm having trouble with an integration problem.

 

 

2π × integral between 0 and 6 of (0.02x^3-0.39x^2+1.77x+0.18) × (sqrt(0.0036x^4-0.0936x^3+0.8208x^2-2.7612x+4.1329)) dx

 

Does anyone know how to solve it or have any suggestions?

 

Thanks heaps!

 

The numbers in this integral seem to be very irregular, so I don't think you have to solve this by hand. Using my Ti-84, the answer is: 82.6

Here are the workings:

 

post-115475-0-46872500-1430820110.png, post-115475-0-59185200-1430820115.png, post-115475-0-67872200-1430820129.png

 

Hope this helps :)

Edited by Vioh
  • Like 1
Link to post
Share on other sites

 

Hi!

 

I'm having trouble with an integration problem.

 

 

2π × integral between 0 and 6 of (0.02x^3-0.39x^2+1.77x+0.18) × (sqrt(0.0036x^4-0.0936x^3+0.8208x^2-2.7612x+4.1329)) dx

 

Does anyone know how to solve it or have any suggestions?

 

Thanks heaps!

 

The numbers in this integral seem to be very irregular, so I don't think you have to solve this by hand. Using my Ti-84, the answer is: 82.6

Here are the workings:

 

attachicon.gifa1.png, attachicon.gifa2.png, attachicon.gifa3.png

 

Hope this helps :)

 

This helps thanks! But I also need to show the working for this problem. Would you know how to do this?

 

Thank you so much!

Link to post
Share on other sites

 

This helps thanks! But I also need to show the working for this problem. Would you know how to do this?

 

If this is part of your IA or something similar, then the photographs of the calculator themselves can be used to show the working for the problem. On the other hand, if this problem is in the IB exam for example, then you don't really need to show any workings at all. It is enough to just say: Using the GDC (graphic display calculator), the answer to this integral is 82.6 :)

  • Like 1
Link to post
Share on other sites

 

 

This helps thanks! But I also need to show the working for this problem. Would you know how to do this?

 

If this is part of your IA or something similar, then the photographs of the calculator themselves can be used to show the working for the problem. On the other hand, if this problem is in the IB exam for example, then you don't really need to show any workings at all. It is enough to just say: Using the GDC (graphic display calculator), the answer to this integral is 82.6 :)

 

Ok thank you for all your help :)

Link to post
Share on other sites

I'll cast a shade of doubt... when I copied the integral to Wolfram Alpha, it showed the result as 13.1478

http://www.wolframalpha.com/input/?i=integrate+%280.02x%5E3-0.39x%5E2%2B1.77x%2B0.18%29*%28sqrt%280.0036x%5E4-0.0936x%5E3%2B0.8208x%5E2-2.7612x%2B4.1329%29%29+dx+from+x%3D0+to+6

 

Edit: my bad, forgot to multiply it by 2*pi, it is 82.61 in the end.

Edited by Slovakov
  • Like 2
Link to post
Share on other sites

 

oh, I think that's because you forgot to put the 2pi in front of it. Notice that 2pi * 13.1478 = 82.6 :)

  • Like 2
Link to post
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...