Djsporting Posted January 30, 2016 Report Share Posted January 30, 2016 Could anyone help me with this question? The correct answer is D, but i'm unsure as to why? Reply Link to post Share on other sites More sharing options...
kw0573 Posted January 30, 2016 Report Share Posted January 30, 2016 (edited) Brewster's anglehttps://en.wikipedia.org/wiki/Brewster%27s_angleIn SL (since we don't have multiple choice questions for the option), we looked at both polarized light and the 90 degrees between reflected and refracted light, but we didn't do much calculations with it. So according to this link, the n for the medium in which light is refracted goes on top, n for reflected medium goes on the bottom (n for air = 1).Normally Brewster's angle is defined with the incident ray and the normal, but here it's the 90-theta_b.What happens for tan is that it relates opposite over adjacent sides. When you do 90 - theta, opposite and adjacent are switched, orarctan x + arctan (1/x) = pi / 2, Edited January 30, 2016 by kw0573 2 Reply Link to post Share on other sites More sharing options...
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