masochist, on May 12, 2010 - 15:02, said:
can some one help me out with this q?
i don't know how to do it

i don't know how to do it

To explain:
Every amino acid has a tRNA molecule.
Every tRNA molecule has an anticodon of 3 nucleotides.
Every tRNA must slot onto codon of the mRNA, which is also 3 nucleotides long.
So in short, every amino acid is coded for by 3 bases/nucleotides (via tRNA). Therefore however many amino acids there are, there should be about 3x as many nucleotides as there are amino acids on the mRNA. Hope that makes sense.
And to answer your second question, the answer is A.
That's because a test cross is a recessive parent - i.e. aa as their genotype. Half of the offspring express the dominant gene, and half don't. That means the parent you're interested in must have the dominant gene (otherwise none of the offspring would, there's nowhere else for it to come from!). However, if your parent was homozygous and had both AA genes, that wouldn't explain the fact that half of the offspring are recessive. ALL of the offspring would be recessive, because there's no offspring which wouldn't have Aa as their genotype and therefore express the trait in their phenotype.
As half of the offspring are recessive and therefore aa and the other half dominant and therefore Aa, you can deduce that the parent must have Aa as their genotype. Therefore they're heterozygous
To do it as one of those chart things:
AA x aa
= Aa, Aa, Aa, Aa
= Aa as the only outcome
aa x aa
= aa, aa, aa, aa
= aa as the only outcome
Aa x aa
= Aa, aa, Aa, aa
= Aa and aa as the outcomes in a 50/50 ratio <--- describes the scenario.
The trait can't be polygenic because otherwise there wouldn't be just two outcomes, there'd be a gradient with some partly expressing, some fully expressing, some expressing a little bit less than fully but more than partly... etc. xP


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