Msj Chem

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About Msj Chem

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    Male
  • Exams
    May 2016
  • Country
    Japan

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  1. Maybe this will help:
  2. If you took repeat trials in your lab, then you should average the change in mass between the pure Mg and the compound MgO.
  3. Maybe these videos will help:
  4. Try here:
  5. Maybe this will help:
  6. Ka is the acid dissociation constant and Q is the reaction quotient. Do you mean Kc and Q? Is so, maybe this video will help:
  7. Maybe this video will help: https://youtu.be/FbD5TTKGI-w
  8. http://www.msjchem.com/sl-option-c.html
  9. You are free to answer whichever option you want in the exam. My advice would be to answer the option that you have studied before of course.
  10. At SL, you only need to know that halogenoalkanes undergo SN reactions to form alcohols. The mechanisms and kinetics (unimolecular and bimolecular) are not required at SL.
  11. 28. The aluminum ion has a high charge density and is able to hydrolyse water molecules to produce H+ ions in solution and a decrease in pH. 29. A buffer solution should have equal amounts of a weak acid and the salt of the weak acid and strong base. Whichever choice gives you that is the correct answer.
  12. I have worksheets for this topic on my website. Maybe they will be helpful. http://www.msjchem.com/topic-13-periodicity-hl.html
  13. From May 2016 subject report (Copyright IB). Component grade boundaries Grade: 1 2 3 4 5 6 7 Mark range: 0 - 3 4 - 6 7 - 10 11 - 13 14 - 16 17 - 19 20 - 24
  14. You can find two videos on pH curves on my website here: http://www.msjchem.com/topic-18-acids-and-bases-hl.html Syllabus details can be found here, (see 18.3 pH curves). http://www.msjchem.com/uploads/1/1/1/1/11113745/topic_18.pdf
  15. 10.0 mol of C2H3Cl would require 25 mol of O2 to react completely because of the 2:5 molar ratio. 10.0 mol of O2 requires 4 mol of C2H3Cl to react and seeing as we have 10.0 mol, that makes O2 the limiting reactant. The ratio of the limiting reactant O2 to H2O is 5:2, therefore 10.0 mol of O2 will produce 4 mol of H2O.