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    May 2019
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  1. ALO

    Math IA Help - Graphing

    Thank you!
  2. ALO

    Math IA Help - Graphing

    I don't quite understand how E = kl/r^4 would be proportional to 1/r^4. and if E does = 1/r^4, what does it mean? I am sorry for asking too many questions, it's just that I feel more confused now
  3. ALO

    Math IA Help - Graphing

    hmm. I actually don't have values for E and r as of yet, as I assume I have to do it later. I need to find out what type of relationship there is between E and r. know
  4. ALO

    Math IA Help - Graphing

    no. I get this: And also in the equation I mentioned k is a constant, 9. Is there another way I can make this graph into a linear?
  5. ALO

    Math IA Help - Graphing

    Hello, I've been been working on my Math IA, and I suddenly got stuck when I came up with this graph: I know it can't be exponential....oh and also the base equation for this graph is E = kl/r^4
  6. ALO


    Hello to all, Okay...so I have chosen a math IA topic after finding out that my previous topic was a bit too complex and it was out of the syllabus. But, now for this new topic, I'm stuck with this one part. I have attached a file that has a picture as to what I'm talking about. Its basically a model for a blood vessel. Now I want to write and equation for the total energy loss which could be modeled by E = E1 + E2 = kl1/r14 + kl2/r24. However when I try solving for l1 and l2 in terms of θ, and then substituting it within the equation, I end up with a quite odd looking function, which I can't graph. I think I'm doing something wrong but I just don't get what it is. The equations I am getting for l1 and l2 in terms of θ, are: - l2 = 20/sinθ or 20 - l1/cos θ - l1 = - l2 (cos θ) + 20 or 20 - 20(tanθ)/tanθ Oh and the values I used for the variables are: a = 20mm (2cm), b = 20mm (2cm), r1=6mm, r2= 2mm

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