energetic Posted May 29, 2011 Report Share Posted May 29, 2011 i don't getthe point about matrices.. anyway how should this be solved to form a matrix:554.8 =(a)(1950^3)+(b)(1955^2)+©1950+(d)729.2=(a)(1965^3)+(b)(1965^2)+©1965+(d)998.9=(a)(1980^3)+(b)(1980^2)+©1980+(d)1220.5=(a)(1995^3)+(b)(1995^2)+©1995+(d)how to solve for a,b,c,d Reply Link to post Share on other sites More sharing options...
dessskris Posted May 29, 2011 Report Share Posted May 29, 2011 well for example you have this system of equations: 5x1+3x2+5x3=23 6x1+4x2+6x3=28 5x1+4x2+6x3=27 to get the values of x1, x2 and x3 you can solve it by substitution or elimination, but you know it's going to take a lot of effort so matrices exist to solve your problem. how? by expressing it into a matrix form as follows: what do you do then? well there are 2 methods: using inverse and rref. both can be done with the help of technology (and only with the help of technology in your level) (rref is taught in Math HL and inverse of 3x3 is taught in university level) do you roughly know what to do now? Reply Link to post Share on other sites More sharing options...
IB-Adam Posted May 29, 2011 Report Share Posted May 29, 2011 As dessskris said, it takes less effort solving equations by using matrices. The more unknown variables you have, the better it is to solve for them using matrices. However, in the beginning it is easy to make silly mistakes, from my own personal experiences. Lev med det, IB är jobbigt 1 Reply Link to post Share on other sites More sharing options...
timtamboy63 Posted May 31, 2011 Report Share Posted May 31, 2011 Yep augmented matrices making solving 3x3 equations waay faster. Though yeah, matrix algebra is retarded Reply Link to post Share on other sites More sharing options...
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