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Portfolio Type II -- The Dice Game


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Ok, so i have managed to create formulas that allow for the calculation of the probability of Bob (regardless of how many times he rolls) if Ann rolls only once, and for the probability of Ann (regardless of how many times she rolls) if Bob only rolls once, now how do i take into account the decrease in probability if the other party is allowed to roll more than once?

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is therre any reasonable or sencible way to figure out the costs and pay offs? obviously you have them in ratio to each other and multiplyable by any constant to give variance and option as to how much one wants ot gamble but i mean do you just have to do it by ear or is there some actually mathematical way to do it

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  • 2 weeks later...

So wat if she wins the first time and doesnt wanna throw twice ?? tongue.giftongue.gif ??

You are - of course - allowed to make it more complicated than it already is. . .

But I don't think that this 'can' is really that relevant, or did you get a different result then?

Absolutely positive is correct, even if she does get a higher number the first roll its her choice to roll the second time, its not like its going to make a difference.... even if she gets a smaller number then she can always fall back on the 1st bigger number.

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Can anyone please help me out with the part in the portfolio 'The Dice Game' where Ann can roll the dice twice while Bob can only once. The portfolio has to be submitted this week and I can't get past this Question. Please help !!!!

Ahm, yeah.

I calculated the probability that Bob doesn't lose.

So, If he throws a 1 then Ann has to throw 11 - 1 combination.

If he throws a 2, then Ann has to throw 11, 21, 12 or 22 - 4 combinations...

And so on till 6. Therefore Ann has 36 possible combinations.

In the end it's 1 - (some kind of formula you should get) | And the 1 in the beginning is important as you want it for Ann.

So the thing is that in the question it is said that she 'can' throw once more, so there is a probability that she doesnt throw it the second time, that will only be when she wins ( the probability of her winning in d first try was easily calculated in the previous question being 15/36) so if she looses that ( probability of 21/36) will she win when she throws it d second time ?

you guys aren't seeing how much Bob wins but seeing for Ann's wins... so if Bob is rolling once and ann twice go to excell and type things into columns

Bob's first row- the first 36 rows are 1, next 36 are 2. then the next column for Ann is her 1st roll where the first 6 you can put 1 then the next 6 you can put 2 so by the time the 1st round of 1's in bobs 1st 36 rows are over you'll have gone through 6 sets of 1,2,3,4,5,6 and then the 3rd column is her second roll and here you just put 111111 the 1st six rows then 22222 the next 6 and just continue until you have finished.. on excell after having labelled the 1st row and starting your values on the 2nd row your list should stop at row 217... and then calculate the probability of Ann winning.. then create a simulation.. and see if the probability within the simulation fits your "hypothesis"/ "predicted" probability (the one from your set trials like i explained above..) and then figure out a formula for this situation :)

good luck.. so far ive gotten up to 3 and i cant figure out what the modelling one is asking me to do! i don't know anything about casinos or wtv.. HELP!

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so who has finished this task and is able to give a little more guidance?

so in the fourth question, the player will win if their score is higher than the bank's and the player will lose (i.e. the bank will win) if their score is the same with the bank's? what will happen if the player's score is lower than the bank's?

wouldn't the best game be a fair one? like when the probability of winning for the player and for the bank are the same?

can anyone hint me on the last question with multiple players?

read the question again carefully it says if the player rolls a number that is the same as or less than the number that the casino/bank rolls then the player looses so if im the player and youre the bank:

you (the bank) roll a 4

To win i have to roll a 5 or 6. if i roll a 1,2,3,4 i will lose..

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  • 4 weeks later...

I need help with the third bullet point, where Bob rolls three times and Ann rolls three times.

I tried to manually count the possible ways for a score of 1, 2, 3, 4, 5, 6 for Bob to be taken, but I seem to miss out some possibilities because they are not adding up to 216.

Could someone please post the possible ways for each score? Like how many ways can Bob get a 1, 2, 3, and so on.

Thank you.

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I don't have a general formula either. I only did calculations for Bob 3 and Ann 3.

My teacher told us to think about the possible ways a score of 1, 2, 3, 4, 5, 6 and you should be able to spot a pattern. I kinda did see something but it wasn't conclusive enough so I just ignored the general formula.

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is therre any reasonable or sencible way to figure out the costs and pay offs? obviously you have them in ratio to each other and multiplyable by any constant to give variance and option as to how much one wants ot gamble but i mean do you just have to do it by ear or is there some actually mathematical way to do it

Thinking about this part as well. What is the lowest possible winning of a game to be set in relation to the price of playing, so that the player is actually willing to play? My teacher told me to 'make research' but I don't seem to get what exactly is required.

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I mean in my opinion, as long as the game isn't biased towards the bank or players anything is acceptable.

I was under the impression that as with all casino games, it was supposed to be biased towards the bank overall (but theres still some players who make money from it)

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I mean in my opinion, as long as the game isn't biased towards the bank or players anything is acceptable.

The casino is supposed to expect a profit. Thus, the game is designed in such a way that the bank has an advantage. The model is also created in such a way that the casino expects to get paid more than they give out. It is just an EXPECTATION and so there will be cases that the player wins. It may even be possible that the casino makes a loss.

Your goal is to make the profit of margin for the casino as large as possible, but bear in mind that it still has to be enticing enough for the players to want to play the game.

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  • 3 weeks later...

I will post the general formula and I hope it helps all of you here.

It was derived from the manual calculations I did for the cases where Ann and Bob rolls (1, 1), (2, 1), (1, 2), (2, 2), (3, 1), (1, 3), (3, 2), (2, 3), and (3, 3), respectively.

The general formula that a gambler wins against the bank in a one to one gamble is:

http://t.co/WStexllrVW, where x is the number of times the gambler rolls, and y is the number of times the bank rolls.

I know it works since I tested it with more than 50 different pairs of x and y values using a program I wrote to test this.

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I always write my intros the same... For Chemistry, Physics or Math. Very straight forward and without beating around the bush. The purpose of this investigation is to create a new casino game, stuff like that. Write what you expect to be doing in this investigation and how you intend on finishing it. Just write about the investigation in general and you should be pretty good. What's nice about Math IA's is they're designed to segue very nicely into the next bullet point too, so transitions are simple enough where you can just say, now we're going to try add this variable to see what happens.

Say first you will be looking at the probability of each of the players winning if they roll only once, then if Ann rolls twice and Bob continues to roll only once. Follow the bullet points to guide your introduction as well as your investigation.

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@01061055 Thanks for the help! One more thing....im sure i should have asked this along with my last post, but the conclusion should not be answering any question directly right? Any particular way to go on about with the conclusion? Thanks once again!!

Edited by Amessed
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