miamonique Posted July 7, 2011 Report Share Posted July 7, 2011 I'm doing my EE in biology and I need to calculate the significance of my results. I tried using the 2 sample t-test, but I have no idea of what I'm doing!Anybody got any experience in this? Reply Link to post Share on other sites More sharing options...
El Che Posted July 7, 2011 Report Share Posted July 7, 2011 If you tell me your values maybe I can help you state the significance. Reply Link to post Share on other sites More sharing options...
miamonique Posted July 7, 2011 Author Report Share Posted July 7, 2011 If you tell me your values maybe I can help you state the significance.Well, It's kind of difficult knowing which values to list.I have values of initial weight and final weight of my samples, and also their percentage weight loss.In my investigation I have two groups, and the null hypothesis is that they have no significant differences in weight loss at different temperatures.Do you need the average value of percentage weight loss for each temperature?I have roughly nine samples at each temperature in both groups. That is, 36 samples (initial weight, final weight, percentage weight loss) for each group. Reply Link to post Share on other sites More sharing options...
miamonique Posted July 7, 2011 Author Report Share Posted July 7, 2011 Oh, my. I don't know if that was understandable.It's quite difficult trying to explain something you've gotta that far into. Reply Link to post Share on other sites More sharing options...
El Che Posted July 7, 2011 Report Share Posted July 7, 2011 Since you are testing the difference of two samples in weight loss in different temperatures you will definitely need the mean of percentage loss for both groups in order to do the t-test. Then you find the standard deviation for the groups. Having these values it is not hard to calculate for the t value using the following formula: http://www.nursingplanet.com/biostatistics/t-test-formula.jpgOnce you have the t value you calculate the degrees of freedom (total number of samples, thus 18 for yours minus 2). Then use the 0.05 column of the table for critical values of t and you will see a value (2.12). If your t is below the critical value, i.e. 2.12 the results are not significantly different and therefore you accept your null hypothesis. If your t is above 2.12, the results are significantly different and you reject the null hypothesis. If you need further clarification let me know! =) Good luck! 1 Reply Link to post Share on other sites More sharing options...
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