Guest SlimShadyFan Posted April 8, 2012 Report Share Posted April 8, 2012 I'm doing an experiment and have these values: Initial temperature: 21.0°C ± 0.5°C Final temperature: 63.0°C ± 0.5°C (1st trial) 60.0°C ± 0.5°C (2nd trial) So the average change in temperature is 40.5°C. Now I need help with my uncertainties. I'm not sure how to find it out. Do I just add all the uncertainties and get ± 2? Please help me Link to post Share on other sites More sharing options...
CkyBlue Posted April 8, 2012 Report Share Posted April 8, 2012 Carry out your uncertainty calculations as you would normally. Remember when summing or subtracting unit values, the uncertainties add.first value: (63.0°C ± 0.5)-(21.0°C ± 0.5)= 42.0± 1.0second value (60.0°C ± 0.5)-(21.0°C ± 0.5)= 39.0± 1.0You know the average is the sum of the first and second values divided by 2. When dividing non-unit values, you simply divide the uncertainty with the averaged value. Don't get this confused when you must add the percentage uncertainties for values with units.average value:=[(42.0± 1.0)+(39.0± 1.0)]/2=(81.0± 2.0)/2=40.5±1.0Sorry for not throwing the Celsius units in there. Link to post Share on other sites More sharing options...
Guest SlimShadyFan Posted April 10, 2012 Share Posted April 10, 2012 · Hidden by CkyBlue, April 11, 2012 - thank you post Hidden by CkyBlue, April 11, 2012 - thank you post Oh was it really that easy? Haha thanks a lot! I actually WAS looking at percentage uncertainties but didn't quite know how to use them. Well this is quite straight forward. Link to post
Survival Robot Posted April 11, 2012 Report Share Posted April 11, 2012 Automatic generated message This topic has been closed by a moderator. Reason: Question answered. If you disagree to this action, please report this post, and a moderator or administrator will reconsider it. Kind regards, IB Survival Staff Link to post Share on other sites More sharing options...
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