Keshuv19 Posted August 12, 2013 Report Share Posted August 12, 2013 Hi guys can you please help me out with the solving of this quadratic equation asap .Question :Find the range of values of m such that for all x m(x+1) is less than and equal to x^2.(PS : if did not understand above, then check attachment).thnx Reply Link to post Share on other sites More sharing options...
tienvu95 Posted August 12, 2013 Report Share Posted August 12, 2013 m(x+1)≤x2x2-mx-m≥0(x2-2×0.5m×x+(0.5m)2)-(0.5m)2-m≥0(x-0.5m)2+(-m2/4-m)≥0since (x-0.5m)2≥0 ∴(-m2/4-m)≥0 (For the eqn to be true for all value of x )∴-m2-4m≥0m2+4m≤0m(m+4)≤0-4≤m≤0 2 Reply Link to post Share on other sites More sharing options...
Keshuv19 Posted August 12, 2013 Author Report Share Posted August 12, 2013 Thankyou Reply Link to post Share on other sites More sharing options...
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