# Quantitative: (NH4)2Ni(SO4)2â€¢6H2O - calculate NH4+?

## Recommended Posts

Hello, I've never been good in quantitative chemistry and once again this kind of question seems to be a trouble for me ehh

I would be so grateful for showing the exact working.

0.040 mol of (NH4)2Ni(SO4)2â€¢6H2O is dissolved in water to give 200 cm3 of aqueous solution.
What is the concentration, in mol dmâ€“3, of ammonium ions?

##### Share on other sites

Hello, I've never been good in quantitative chemistry and once again this kind of question seems to be a trouble for me ehh

I would be so grateful for showing the exact working.

0.040 mol of (NH4)2Ni(SO4)2â€¢6H2O is dissolved in water to give 200 cm3 of aqueous solution.

What is the concentration, in mol dmâ€“3, of ammonium ions?

Okay so you would use the formula C (concentration) = n (number of moles) / V (Volume in dm3)

So first you would convert 200 cm3 to dm3 which would be 0.2 dm3

annd then simply substitute the number you have in the formula so C = 0.04/0.2 = 0.2 moles.

However, you have 2 of the NH4 so you multiply 0.2 x 2 = 0.4. There's your answer!

Hope this helps!

• 1

## Create an account

Register a new account