Jump to content
Sign in to follow this  

May15 Physics SL

Recommended Posts

How did it go for the Tz2 paper Physics guys? I was unsure about quite a few in paper 1 but I think paper 2 was easier. Some paper 1 questions were so different from past papers or is it only me??

Share this post


Link to post
Share on other sites

In p1 there was a lot of guessing :/ There was one question with two magnets in which I thought the force direction would be out of the page, but none of the four options made sense to me.

P2 I did question 5 in section B. SHM was a gift and then as much as I hate electric currents, think I did quite alright in the Part 2. However, question 1 really put me off haha

Share this post


Link to post
Share on other sites

In p1 there was a lot of guessing :/ There was one question with two magnets in which I thought the force direction would be out of the page, but none of the four options made sense to me.

P2 I did question 5 in section B. SHM was a gift and then as much as I hate electric currents, think I did quite alright in the Part 2. However, question 1 really put me off haha

 

Yes I remember that question. I just guessed A but I was so confused with the magnetic field, I couldnt figure it out either.

 

oh nice. I did question 5 as well. Yes, I loved the SHM question as well. I thought it was so simple. I was just a bit scared about the last two questions on electric currents. I got the current to be something like 0.4545 and the volt to be 6 V. What did u get for ii for current and the voltage? And how did u do the last power question?

 

How did you do the displacement question in Section A. What did u get for it? I think i got something like 5.6 m.

Share this post


Link to post
Share on other sites

The magnet one was difficult to understand, the north pole is on the inner side of the magnet (there was a small arrow at the bottom) so force was going down and answer was C. 

For the Electric currents, I think I got the exact same results, V was 6 and Current at 0.4545 and the power question I just multiplied them. Which is odd cause it was worth 3 marks and the answer was too simple!

For the displacement I did one of the Suvat formulas. V^2 = U^2 + 2as. To calculate the acceleration I used the friction minus the result in the Mg sin X question and got a force of 37 or something like that, F=ma, found the a. The final Velocity was 0, and they tell us the initial one, so just calculate for s. The only thing that worries me is that I got the force calculations wrong. Hopefully not. 

Share this post


Link to post
Share on other sites

Elevator and Force meter.. someone please confirm. One of the people I asked said that since whatever force the downward acceleration causes on the person, it also causes it on the force meter (given that they are both in the elevator together). So the answer should be Mg only. Some people said mg+ma! Can anyone confirm? Also the Albedo question was tricky :( What about the graph for the resistance? That had V and I as axis? Being a linear graph seemed too easy an answer so I didnt choose it! lol XD

Share this post


Link to post
Share on other sites

The magnet one was difficult to understand, the north pole is on the inner side of the magnet (there was a small arrow at the bottom) so force was going down and answer was C. 

For the Electric currents, I think I got the exact same results, V was 6 and Current at 0.4545 and the power question I just multiplied them. Which is odd cause it was worth 3 marks and the answer was too simple!

For the displacement I did one of the Suvat formulas. V^2 = U^2 + 2as. To calculate the acceleration I used the friction minus the result in the Mg sin X question and got a force of 37 or something like that, F=ma, found the a. The final Velocity was 0, and they tell us the initial one, so just calculate for s. The only thing that worries me is that I got the force calculations wrong. Hopefully not. 

 

I wrote Mg + ma as well because I messed up the sign in the exam but it was (Mg - ma). 

Edited by IBsurvivor2015May

Share this post


Link to post
Share on other sites

Not that one, I mean the MC question with graphing of V against I .. 

 

 

 

Not that one, I mean the MC question with graphing of V against I .. 

 

Oh I picked A. The linear graph but starting above 0.

 

The question with the graph of V against I showed up in I believe the may 2012 paper and the answer started at 0,0 and went up sort of curved :( 

 

The displacement for section A, I got 5.something.

  • Like 1

Share this post


Link to post
Share on other sites

You know the question when the guy was going down the hill on a bike? When he was breaking, did you get something like 5 meters for him to stop completely?

Edited by Badalyan
  • Like 1

Share this post


Link to post
Share on other sites

You know the question when the guy was going down the hill on a bike? When he was breaking, did you get something like 5 meters for him to stop completely?

You should use F S= mv^2 /2

Share this post


Link to post
Share on other sites

I was not asking about what you should use tbh:/ I was asking what you got for the answer :) 

 

PS: You were given net breaking force, so you could find acceleration from dividing the force by the mass. Then you could use that acceleration in order to calculate the distance since you know u and v (using v^2 = u^2 + 2as)

So not sure about the method you suggested there :wacko:

 

 

You know the question when the guy was going down the hill on a bike? When he was breaking, did you get something like 5 meters for him to stop completely?


You should use F S= mv^2 /2

 

  • Like 1

Share this post


Link to post
Share on other sites

 

I was not asking about what you should use tbh:/ I was asking what you got for the answer :)

 

PS: You were given net breaking force, so you could find acceleration from dividing the force by the mass. Then you could use that acceleration in order to calculate the distance since you know u and v (using v^2 = u^2 + 2as)

So not sure about the method you suggested there :wacko:

 

 

You know the question when the guy was going down the hill on a bike? When he was breaking, did you get something like 5 meters for him to stop completely?

You should use F S= mv^2 /2

 

 

The guy above you said he got 5. I also used the same method (Stated above as well), I just don't remember the exact values, so I can't tell you. Either way don't worry, seems like we got it correct. 

  • Like 1

Share this post


Link to post
Share on other sites

Why was it mg-ma and also the graph, was it straight or curved like a filament lamp. - for paper 1. Also who else did question 4 and what did you guys get for the halflive problem i got 16.8 but im sure thats wrong.

Share this post


Link to post
Share on other sites

Why was it mg-ma and also the graph, was it straight or curved like a filament lamp. - for paper 1. Also who else did question 4 and what did you guys get for the halflive problem i got 16.8 but im sure thats wrong.

Guys what was the graph for and what was on the y and x axis?

Share this post


Link to post
Share on other sites

Why was it mg-ma and also the graph, was it straight or curved like a filament lamp. - for paper 1. Also who else did question 4 and what did you guys get for the halflive problem i got 16.8 but im sure thats wrong.

 

Do you remember if the elevator was accelerating downwards or upwards??

Share this post


Link to post
Share on other sites

@ibsurvivior downwards. My thinking was, that since the elevator is going down, it would add more force due to the accelration which could be shown as MxA and so mg and add the acceleration of elevator going down = mg+ma? tell me what you guys think?

Share this post


Link to post
Share on other sites

 

Why was it mg-ma and also the graph, was it straight or curved like a filament lamp. - for paper 1. Also who else did question 4 and what did you guys get for the halflive problem i got 16.8 but im sure thats wrong.

 

Do you remember if the elevator was accelerating downwards or upwards??

 

downwards

Share this post


Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
Sign in to follow this  

×

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.