just a simple chemistry question

[[m a a r i.]]

im just stuck in one of my past paper homework.

well it must be pretty easy for the IB1 and IB2 who have learned stoichiometry for chemistry already.

well i dont know how to do this question, i just cant figure it out

Question : How many oxygen atoms are present in 0.0500mol carbon dioxide.

please can you show me the working as i just dont know how to solve it, thanks

[~Lc~]

you have to find the number of moles of oxygen basically.

1 mole= 6.02* 10^23 atoms according to avegadros constant

the chemical formulae of Carbon Dioxide is CO2 so there is 2 oxygen atoms for every carbon atom, so to find the number of moles of oxygen multiply the # of moles of the compound by 2 so:

2* 0.05 = 0.1 mol of Oxygen

mol #of atoms

1 6.02*10^23

.01 x

cross multiply: 0.1 * 6.02*10^23= 6.02*10^22 atoms

[[m a a r i.]]

you have to find the number of moles of oxygen basically.

1 mole= 6.02* 10^23 atoms according to avegadros constant

the chemical formulae of Carbon Dioxide is CO2 so there is 2 oxygen atoms for every carbon atom, so to find the number of moles of oxygen multiply the # of moles of the compound by 2 so:

2* 0.05 = 0.1 mol of Oxygen

mol #of atoms

1 6.02*10^23

.01 x

cross multiply: 0.1 * 6.02*10^23= 6.02*10^22 atoms

THANKS LOADS LC.

FINALLY GET IT