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just a simple chemistry question

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im just stuck in one of my past paper homework.

well it must be pretty easy for the IB1 and IB2 who have learned stoichiometry for chemistry already.

well i dont know how to do this question, i just cant figure it out

Question : How many oxygen atoms are present in 0.0500mol carbon dioxide.

please can you show me the working as i just dont know how to solve it, thanks -_-

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you have to find the number of moles of oxygen basically.

1 mole= 6.02* 10^23 atoms according to avegadros constant

the chemical formulae of Carbon Dioxide is CO2 so there is 2 oxygen atoms for every carbon atom, so to find the number of moles of oxygen multiply the # of moles of the compound by 2 so:

2* 0.05 = 0.1 mol of Oxygen

mol #of atoms

1 6.02*10^23

.01 x

cross multiply: 0.1 * 6.02*10^23= 6.02*10^22 atoms

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you have to find the number of moles of oxygen basically.

1 mole= 6.02* 10^23 atoms according to avegadros constant

the chemical formulae of Carbon Dioxide is CO2 so there is 2 oxygen atoms for every carbon atom, so to find the number of moles of oxygen multiply the # of moles of the compound by 2 so:

2* 0.05 = 0.1 mol of Oxygen

mol #of atoms

1 6.02*10^23

.01 x

cross multiply: 0.1 * 6.02*10^23= 6.02*10^22 atoms

THANKS LOADS LC.

FINALLY GET IT -_-

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