Guest Posted April 11, 2016 Report Share Posted April 11, 2016 Hello. I need help deriving this equation using the quotient rule. I'm having difficulty reaching the correct answer because I've no idea what I'm doing wrong. Quotient Rule: (u'v - v'u) / (v2) Equation to derive: (2x-3) / (x2) What I did: u= 2x-3 v= x2 u'= 2 v'= 2x *sustituted into equation to get: -( 2x2 - 6x) / x4 The answer should be - (2x - 6) / x3 What am I doing wrong? Reply Link to post Share on other sites More sharing options...
deftdog18 Posted April 11, 2016 Report Share Posted April 11, 2016 u= 2x-3 , u' =2 v= x^2 , v'=2x Using quotient rule, = (x^2(2) - 2x(2x-3))/x^4 = (2x^2- 4x^2 +6x )/x^4 = -2x^2+6x/ x^4 Which can be simplified as -(2x^2 -6x)/x^4 Seems like you got the correct answer here.. maybe the answer is wrong? I checked with cymath as well (http://www.cymath.com/answer.php?q=differentiate%20%20(2x-3)%20%2F%20(x2)), same answer. Reply Link to post Share on other sites More sharing options...
King112 Posted April 11, 2016 Report Share Posted April 11, 2016 You've got the right answer. you can divide the equation by x and you'll get 2x-6 divided by x3. Just divide through by x. Cheers, King112 Reply Link to post Share on other sites More sharing options...
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