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Probability question


allthebest

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Same logic in b) and c), I'll only do b)
P(X) = favourable outcomes / total outcomes
if X = 7, there can be 3 choices for the largest number. There can be (6 choose 2) choices of the two smaller numbers. The product of these two independent combinations are divided by total outcome: (10 choose 4)
3 * 6C2 / 10C4 = 3 * 15 / 210 = 3/14. 
Similar logic for c)

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