Amy0501 Posted July 4, 2016 Report Share Posted July 4, 2016 (edited) Hey, my teacher is giving us past papers as H.W. and I was wondering if anyone knew how to solve this one. Im kind of stuck. g is a quadratic function where g(0)=5. Its symmetry axis is x=2. Find the equation of g expressed as a(x-h)"2 +3 Edited July 4, 2016 by Amy0501 Reply Link to post Share on other sites More sharing options...
kw0573 Posted July 4, 2016 Report Share Posted July 4, 2016 (edited) Recognize that an untransformed quadratic function has symmetry on x = 0. x = 2 symmetry means the graph is horizontally shifted 2 units to the right. That means h = 2. g(0) = 5 is point on the curve. g(0) = a(0 - h)2 + 3 = a(0 - 2)2 + 3 = 4a + 3 = 5 ==> 4a = 2, a = 1/2 EDIT: formal answer would be g(x) = 1/2 * (x - 2)2 + 3 One way to visualize the solution is to understand as it stands, both a and h are unknown so you need some separate information for solve for each. So one thing to practise is converting the written information (symmetry axis is x = 2) to a mathematical one (horizontal shift is 2 units to the right). Edited July 4, 2016 by kw0573 Reply Link to post Share on other sites More sharing options...
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