Recycle Bin Posted December 26, 2016 Report Share Posted December 26, 2016 Reply Link to post Share on other sites More sharing options...
Vioh Posted December 26, 2016 Report Share Posted December 26, 2016 Clearly the "horizontal normal" force mentioned here is the centripetal force that drives the circular motion of the cyclist. So the answer would be B. This is because the cyclist is moving at a uniform speed, which means that the net force along the direction of motion must be zero. On the other hand, since the cyclist is moving in a circle (i.e. the direction of motion is changing all the time), this acceleration must come from a non-zero centripetal force. 1 Reply Link to post Share on other sites More sharing options...
Recycle Bin Posted December 27, 2016 Author Report Share Posted December 27, 2016 21 hours ago, Vioh said: Clearly the "horizontal normal" force mentioned here is the centripetal force that drives the circular motion of the cyclist. So the answer would be B. This is because the cyclist is moving at a uniform speed, which means that the net force along the direction of motion must be zero. On the other hand, since the cyclist is moving in a circle (i.e. the direction of motion is changing all the time), this acceleration must come from a non-zero centripetal force. it's much clearer now - cheers! Reply Link to post Share on other sites More sharing options...
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