# sl math porfolio

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after you have the math how do you write up the porfolio
and was is the scope or limitations of a, b, and x?

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Well let me remember for the Scop/Limit you say that x can not be zero ( x>0) since logs can never be zero also x is not negative since it cant be negative, umm wat esle...as for a and b that cant not be receprocals, this is the one that u have to explain ok wat u do is get the general stament which is sth like log(basea)X * log(base b)X divded by log(base b)x + log(base a)x ok that is the general stament wat u do is take the denomantaor which is log(base b)x + log(base a)x and write it as log(base b)x + log(base a)x =0 then u re arrnage it and use the changing bases until u are left with ab=1 which means the denomantor is equal to one so that shouldnt be right so Recrocals arent allowed

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[quote name='dexter' post='28430' date='Nov 15 2008, 07:26 AM']Well let me remember for the Scop/Limit you say that x can not be zero ( x>0) since logs can never be zero also x is not negative since it cant be negative, umm wat esle...as for a and b that cant not be receprocals, this is the one that u have to explain ok wat u do is get the general stament which is sth like log(basea)X * log(base b)X divded by log(base b)x + log(base a)x ok that is the general stament wat u do is take the denomantaor which is log(base b)x + log(base a)x and write it as log(base b)x + log(base a)x =0 then u re arrnage it and use the changing bases until u are left with ab=1 which means the denomantor is equal to one so that shouldnt be right so Recrocals arent allowed[/quote]
thank you soo much your a life saver

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[quote name='dexter' post='28430' date='Nov 15 2008, 05:26 PM']Well let me remember for the Scop/Limit you say that x can not be zero ( x>0) since logs can never be zero also x is not negative since it cant be negative, umm wat esle...as for a and b that cant not be receprocals, this is the one that u have to explain ok wat u do is get the general stament which is sth like log(basea)X * log(base b)X divded by log(base b)x + log(base a)x ok that is the general stament wat u do is take the denomantaor which is log(base b)x + log(base a)x and write it as log(base b)x + log(base a)x =0 then u re arrnage it and use the changing bases until u are left with ab=1 which means the denomantor is equal to one so that shouldnt be right so Recrocals arent allowed[/quote]

so ur saying that the answer can't be in the form of a reciprical?
oh dammmnnnnnnnnnnnn...

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