christina.staikos27 Posted January 31, 2017 Report Share Posted January 31, 2017 Please help! I cannot figure out this question: Let a and b denote the roots of the quadratic equation x2 - kx + (k-1) = 0 (a) Express a and b in terms of k (b) Given that a2 +b2 =17, find the possible values of k. Reply Link to post Share on other sites More sharing options...
kw0573 Posted January 31, 2017 Report Share Posted January 31, 2017 (edited) This makes use of viete's theorem, which is HL only. The theorem, applied to a quadratic, says roots add to negative of the coefficient of x (-B) in the form x^2 + Bx + C, and multiply to C. In other words, a + b = -(-k)=k, ab = k-1 a^2 + b^2 = (a+b)^2-2ab = 17 = k^2 - 2(k-1) k^2-2k-15=0, (k-5)(k+3) = 0, k=-3, 5 Or what I mean is that the way the question is set up it asks you to plug -k and k-1 into quadratic formula to essentially prove viete's theorem. I admit it's hard to do if you have no exposure to viete's theorem. Edited February 1, 2017 by kw0573 1 Reply Link to post Share on other sites More sharing options...
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