Recycle Bin Posted February 4, 2017 Report Share Posted February 4, 2017 how do i do b) i)? Reply Link to post Share on other sites More sharing options...
kw0573 Posted February 4, 2017 Report Share Posted February 4, 2017 v'(t) = 0 = 2 - 2sin(2t), sin(2t) = 1, 2t = pi/2, t = pi/4. Note the next angle 5pi/4 exceeds the domain 0 to 2, so pi/4 is the answer. Alternatively, at 0 = 2 - 2sin(2t), you can plug in pi/4 to get LHS = 0, RHS = 2 - 2sin(pi/2) = 2-2*1 = 0, LHS = RHS, pi/4 is k. So the short answer is that this is a differential calculus question, not simply a function question. 1 Reply Link to post Share on other sites More sharing options...
Recycle Bin Posted February 14, 2017 Author Report Share Posted February 14, 2017 On 2/4/2017 at 9:57 PM, kw0573 said: So the short answer is that this is a differential calculus question, not simply a function question. that's why I found it difficult..thank you so much though! 1 Reply Link to post Share on other sites More sharing options...
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