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Normal Distribution Problem help

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Hi guys, I am having trouble to figure out a way to solve the second part of this problem. If anyone could help, that would be great. 

The answer I got for part a is 10.3%

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The key to the second part is to define a new binomial distribution X ~ B(100, answer from a), which is applicable when each apple can take on one of two values: too small, not too small. 

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