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Calculus question help


Destiny of Pi

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Hey guys, 

I was sick and missed some math classes. Here are two questions that I can partially solve them but not for the second part. It would be great if some of you could help me with the steps and process. 

For this question, I got that when x=0.4, y=1.573, but I don't know how to justify whether the approximation if greater or smaller than the actual value. 

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For this question, I found that the Maclaurin series is ln(2) +1/2x+1/8x^2. I wonder how could we use this to solve part b. 

5a9b8a3f0860a_question2.png.3840ff97140db4275d9940405e46caa6.png

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1b. Because slope increases with x and y, and you are always underestimating the derivative, you would be underestimating the value at x = 0.4

2b Limits with indeterminate form (0/0, infinity/infinity etc) can be evaluated by substituting expansions at the desired x value for both numerator and denominator. For example, limit of sin x / x as x approaches 0 can be evaluated as
i) sin x expand at x = 0, is x - x^3 / 6 + ..., x is just x

ii) (x - x^3 /6 + ...) / x  = x / x - x^3/6 / x + ... = 1 - x^3/6 /x + ..., which when evaluated at x = 0, is just 1.

iii) hence for sin x / x at x -->0 the limit is 1. You can do a similar analysis for the desired expression.

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Horizontal asymptotes only at x --> ± infinity. Because f(x) is not real in x <0, x --> + infinity gives asymptote at f(x) = 1. You should get f(x) = 1 as horizontal asymptote from graphing calculator. An alternative (more rigorous) way is to transform the function.

define g(x) = ln (f(x)) = 1/x * ln x

We know that the limit as g(x) of x approaches infinity is 0

f(x) = e^(g(x)), same limit would evaluate to e^0 = 1

Edited by kw0573
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You would use the method of integrating factor (which should be in your textbook). You can also find it online. It's just an application of both e^x derivatives and product rule.

Edited by kw0573
not chain rule
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