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IB Physics topic 2.1projectile motion


jinnn

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hello, so I was trying to solve a question and failed :)... 

An object is launched horizontally with a velocity of 12ms-1. What is the vertical component of velocity after 2.0s? 

What are the coordinates of the object after 4.0s? 

 

I tried using t=v-u/a , but I have no idea where the 12ms-1 goes. help please 

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You should use v = s/t (velocity is displacement over time). Nothing about any acceleration is given so assume there is none.

EDIT: OH I see there's gravity. So for horizontal component, the velocity is still 12 m/s, but for vertical component use u = 0 (no initial downward velocity).

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