jinnn Posted March 26, 2019 Report Share Posted March 26, 2019 hello, so I was trying to solve a question and failed :)... An object is launched horizontally with a velocity of 12ms-1. What is the vertical component of velocity after 2.0s? What are the coordinates of the object after 4.0s? I tried using t=v-u/a , but I have no idea where the 12ms-1 goes. help please Reply Link to post Share on other sites More sharing options...
kw0573 Posted March 26, 2019 Report Share Posted March 26, 2019 You should use v = s/t (velocity is displacement over time). Nothing about any acceleration is given so assume there is none. EDIT: OH I see there's gravity. So for horizontal component, the velocity is still 12 m/s, but for vertical component use u = 0 (no initial downward velocity). Reply Link to post Share on other sites More sharing options...
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