1-2-3 Posted May 4, 2009 Report Share Posted May 4, 2009 I need help with this Normal Distribution question:The heights of boys at a particular school follow a normal distribution with a standarddeviation of 5 cm . The probability of a boy being shorter than 153 cm is 0.705. a) Calculate the mean height of the boys.b) Find the probability of a boy being taller than 156 cm .What I did is:a) ((153 - Mean)/5) = 0.705Mean = 149 cmb) P (X <156)= 1 - P(X </= 156)Using the GDC,1 - normalcdf (-10^99, 156, 150, 5)= 0.115---What the answer says is:(Look at the attached file)What am I doing wrong ? Reply Link to post Share on other sites More sharing options...
moneyfaery Posted May 4, 2009 Report Share Posted May 4, 2009 (edited) a) You know that probability is calculated by P(Z < x-μ/σ)μ=??σ=5x=153Find μ:P(Z < 153-μ/5) = 0.705 {this is given}invNorm(0.705) = 0.5388 {gives value for Z}invNorm(area[,μ,σ])Therefore, Z < 153-μ/5 = 0.5388 and solve for μ to get 150Bad notation, I know, but extra brackets looked ugly.b) Find P(X >156):You can just use the lowerbounds, upperbounds, and values for μ and σ in this casenormalcdf(156,1EE99,150.3,5) = 0.127normalcdf(lowerbound,upperbound[,μ,σ])If you don't enter the values for [,μ,σ], you'll be calculating the values of the Z-index by default. Edited May 4, 2009 by Irene Reply Link to post Share on other sites More sharing options...
lois lee Posted February 28, 2010 Report Share Posted February 28, 2010 hey,i was wondering if that question would be on a higher paper or on a standard paper. i am doing higher and just cant get to grips with maths yet!thanks lo Reply Link to post Share on other sites More sharing options...
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