math hl IA type II radiometric dating

[Guest mr_whatsisname]

i am doing the radiometric dating IA in maths hl and i must say i am in quite a tough spot... i havent got the slightest idea how to conjecture an equation...i dont even have a sample of a Math Portfolio...can i please get some help here? i know there is a sample one but i need to be a vip member to view it...i just need an example....in kindah desperate... thx guys (math is definitely my weakest subject )

[deissi]

1) Thought about switching to SL math? I did it and since you have 4 HLs you could too

2) Have you asked for help from your teacher on this?

[Guest simon_vargas]

Hello, my teacher just gave me also a portfolio on radiometric dating, can anyone please help me, Im kind of lost here

[deissi]

You know, we can't help you unless you tell us what you need to be helped in. So any specific question you'd like to ask?

[negro75]

You know, we can't help you unless you tell us what you need to be helped in. So any specific question you'd like to ask?

Hey im new here i have an example that maybe can be usefull to u but i dont know how to send it if someone could teach me, it can be very helpful at times.

[jofijk]

im doing the same portfolio, and i have no clue where to start

i entered the data from part 1 into microsoft excel and created a scatter plot. the trendline tool gave me an equation for the data: y = 0.0005x4 - 0.0485x3 + 1.8934x2 - 32.269x + 209.8 but when i graph it, most of the points dont work

[Abu]

Try removing the last line so that you can get an exponential decay curve, which is exactly how the points behave when they are modeled.

[minhdaubua]

Hi everyone I'm new here

I'm doing the Radiometric thing too

My guess is that for each roll it is expected that 1/6 of the dice will be 6, thus leaving 5/6 of them.

So perhaps the model would follow a simple decay equation which is Nn = No x (5/6)^n

I tried and it worked. The only prob is that sometimes I happened to be too lucky (or unlucky) to have to throw the dice much more fewer time than expected. It made the graph a little bit messy

But so far I'm stuck with the stuff relating to radiocarbon decay. Can anybody explain to me what is the e doing in the equation? I got quite confused with calculating this thing, let alone the fact that I've assumed too much from wikipedia... Would it do any fatal to my marks?

[IBMan9000]

http://mathworld.wolfram.com/ExponentialDecay.html

This site gives a good explanation on how they obtained the equation from the initial rate of decay. The 'e' is Euler's number, and in this case is used to 'cancel out' the natural logarithm of Ln(N/N0) which was obtained in the final step of the Mathworld website (integration of separated differential equation). If you remember, natural logarithms are logarithms with a base of e, Euler's number.

To brush up on integration of exponents/logarithms: http://ltcconline.net/greenl/courses/116/I...Integration.htm

To brush up on natural logarithms: http://en.wikipedia.org/wiki/Natural_logarithm

http://mathworld.wolfram.com/NaturalLogarithm.html

The Mathworld website helped clarify some linguistic issues with the IA and our non-IB calculus book helped while learning it for the first time.